(2/3a^2+b^2)^3+(2/3a^2-b^2)^3-4/3a^2(2/3a^2+b^2)(2/3a^2-b^2)-10/3a^2b^4

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Solution for (2/3a^2+b^2)^3+(2/3a^2-b^2)^3-4/3a^2(2/3a^2+b^2)(2/3a^2-b^2)-10/3a^2b^4 equation: 


x in (-oo:+oo)

((2/3)*a^2+b^2)^3+((2/3)*a^2-b^2)^3-((4/3)*a^2*((2/3)*a^2+b^2)*((2/3)*a^2-b^2))-((10/3)*a^2*b^4) = 0

((2/3)*a^2+b^2)^3+((2/3)*a^2-b^2)^3+(-4/3)*a^2*((2/3)*a^2-b^2)*((2/3)*a^2+b^2)+(-10/3)*a^2*b^4 = 0

(2/3*a^2+b^2)^3+(2/3*a^2-b^2)^3-4/3*a^2*(2/3*a^2-b^2)*(2/3*a^2+b^2)+(-10*a^2*b^4)/3 = 0

(3*(2/3*a^2+b^2)^3)/3+(3*(2/3*a^2-b^2)^3)/3+(-4/3*3*a^2*(2/3*a^2-b^2)*(2/3*a^2+b^2))/3+(-10*a^2*b^4)/3 = 0

3*(2/3*a^2+b^2)^3+3*(2/3*a^2-b^2)^3-4/3*3*a^2*(2/3*a^2-b^2)*(2/3*a^2+b^2)-10*a^2*b^4 = 0

16/9*a^6-16/9*a^6+12*a^2*b^4+4*a^2*b^4-10*a^2*b^4 = 0

16*a^2*b^4-10*a^2*b^4 = 0

6*a^2*b^4 = 0

(6*a^2*b^4)/3 = 0

(6*a^2*b^4)/3 = 0 // * 3

6*a^2*b^4 = 0

x belongs to the empty set

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